[tex]\log _3\left(x+1\right)+\log _3\left(27\right)=3 \\ \log _3\left(x+1\right)+\log _3\left(27\right)-\log _3\left(27\right)=3-\log _3\left(27\right) \\ \log _3\left(x+1\right)=3-\log _3\left(27\right) \\ \log _3\left(x+1\right)=0 \\ \log _3\left(x+1\right)=\log _3\left(1\right) \\ x+1=1 \\ x=0[/tex]
