Răspuns :
AQBC subântinde un arc de 180°, deci are masurade 180°:2=90°
dac R=10⇒AC diametru=2R=2*10=20cm
AB=(pitagora) √(AC²-BC²)=√(20²-12²)=...=16cm
dac R=10⇒AC diametru=2R=2*10=20cm
AB=(pitagora) √(AC²-BC²)=√(20²-12²)=...=16cm