Răspuns :
1 intreg si 1/ 5 = ( 1 × 5 + 1 ) / 5 = 6/5
[ 6 / 5 - 7 / 10 - ( 6 / 5 - 7 /10 ) ] × 5 / 6 = → le aduc la numitorul comun10
= [ 2×6 / 10 - 7 /10 - ( 12 /10 - 7 /10 )] × 5 / 6 =
= ( 12/10 - 7 /10 - 5 / 10 ) × 5/6 =
= ( 5 / 10 - 5 / 10 ) × 5 / 6 =
= 0 × 5 / 6 =
= 0
[ 6 / 5 - 7 / 10 - ( 6 / 5 - 7 /10 ) ] × 5 / 6 = → le aduc la numitorul comun10
= [ 2×6 / 10 - 7 /10 - ( 12 /10 - 7 /10 )] × 5 / 6 =
= ( 12/10 - 7 /10 - 5 / 10 ) × 5/6 =
= ( 5 / 10 - 5 / 10 ) × 5 / 6 =
= 0 × 5 / 6 =
= 0