deci derivata are 2 radacini
si derivata este
2e^2x * (x²+x+m)+e^2x(2x+1)=e^2x*( 2x²+2x+2m+2x+1)=
=e^2x *(2x²+4x+2m+1)
cum e^x>0
ramane ca
2x²+4x+2m+1 sa aibe excat 2 radacini
adica Δ>0
16-4*2*(2m+1)>0
16-16m-8>0
8-16m>0 | :8
1-2m>0
1>2m
2m<1
m<1/2
m∈(-∞;1/2 ) raspuns corect A
