Vs1 = 20mL HNO3
C1 = 0,3M
Vs2 = 40mL HNO3
C2 = 0,1M
V H2O ad. = 40mL
C1 = n1/Vs1(L) => n1 = C1×Vs1(L) = 0,3×20×10^-3 = 0,006 moli acid
C2 = n2/Vs2(L) => n2 = C2×Vs2 = 0,1×40×10^-3 = 0,004 moli HNO3
n acid total = 0,004+0,006 = 0,01 moli
Vsf = Vs1+Vs2+VH2O ad. = 20+40+40 = 100mL = 0,1L
A. Cf = nt/Vsf = 0,01/0,1 = 0,1M
B. HNO3 - A.T => C = [HNO3] = [H3O+] = 10^-1
pH = -lg [H3O+] = 1
C. HNO3 + H2O => NO3(-) + H3O(+)
Ka = [NO3-]×[H3O+]/[HNO3]
