Răspuns :
Metoda grafica
prima cutie l------l + 35 } total = 162 bomboane
a doua cutie l------l------l------l + 47
162 - ( 35 + 47 ) = 162 - 82 = 80 → suma celor 4 parti egale
80 : 4 = 20 bomboane au ramas in prima cutie, dupa ce s-au consumat 35
20 + 35 = 55 bomboane erau in prima cutie
3 × 20 + 47 = 60 + 47 = 107 bomboane au fost in a doua cutie
Verific: 55 + 107 = 162 bomboane erau in cele doua cutii
prima cutie l------l + 35 } total = 162 bomboane
a doua cutie l------l------l------l + 47
162 - ( 35 + 47 ) = 162 - 82 = 80 → suma celor 4 parti egale
80 : 4 = 20 bomboane au ramas in prima cutie, dupa ce s-au consumat 35
20 + 35 = 55 bomboane erau in prima cutie
3 × 20 + 47 = 60 + 47 = 107 bomboane au fost in a doua cutie
Verific: 55 + 107 = 162 bomboane erau in cele doua cutii
a + b = 162
a |-----| - 35
b |-----|-----|-----| - 47
[tex] \frac{b}{3} = a[/tex]
47 + 35 = 82
162 - 82 = 80
[tex] \frac{80}{4} = 20[/tex]
a = 20 ramase in prima cutie
b = 20 × 3 = 60 ramase in a doua cutie
20 + 35 = 55 bomboane au fost in prima cutie
60 + 47 = 107 bomboane au fost in cea de a doua cutie
a |-----| - 35
b |-----|-----|-----| - 47
[tex] \frac{b}{3} = a[/tex]
47 + 35 = 82
162 - 82 = 80
[tex] \frac{80}{4} = 20[/tex]
a = 20 ramase in prima cutie
b = 20 × 3 = 60 ramase in a doua cutie
20 + 35 = 55 bomboane au fost in prima cutie
60 + 47 = 107 bomboane au fost in cea de a doua cutie