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a fost răspuns

Aranjamente de n luate cate 1 plus combinări de n luate cate 1 ,egal cu 8

Răspuns :

An|1  = n
Cn|1 n/1! = n
n + n = 2n = 8 => n=4
Albatran
n!/(n-1)!+n!/(n-1)!*1!=n+n
2n=8
n=4
as simple as that!!

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