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Combinari de x-2 luate cate 2=21

Răspuns :

Abc112
[tex]{C ^{2} _{x-2}} = 21[/tex]

[tex]x \: \in \: \mathbb{N}[/tex]

[tex]x - 2 > 2 = > x > 4[/tex]

[tex] \frac{(x - 2)!}{2!(x - 2 - 2)!} = 21 [/tex]

[tex]\frac{(x - 2)!}{2(x - 4)!} = 21[/tex]

[tex] \frac{(x - 2)(x - 3)(x - 4)!}{2(x - 4)!} = 21[/tex]

[tex] \frac{(x - 2)(x - 3)}{2} = 21[/tex]

[tex](x - 2)(x - 3) = 2 \times 21[/tex]

[tex](x - 2)(x - 3) = 42[/tex]

[tex] {x}^{2} - 3x - 2x + 6 = 42[/tex]

[tex] {x}^{2} - 3x - 2x + 6 - 42=0[/tex]

[tex] {x}^{2} - 5x - 36 = 0[/tex]

[tex] {x}^{2} - 9x + 4x - 36 = 0[/tex]

[tex]x(x - 9) + 4(x - 9) = 0[/tex]

[tex](x - 9)(x + 4) = 0 [/tex]

[tex]x - 9 = 0 = > x = 9 > 0[/tex]

[tex]x + 4 = 0 = > x = - 4 < 0 \: nu \: convine[/tex]

[tex] = > x = 9[/tex]
C.E.x≥2
(x-2) (x-3)/2=21
(x-2)(x-3)=(x-3)(x-2)=42=6*7
x-3=6
x-2=7
x=9∈Domeniului de existenta
(x-2)(x-3) crescatoare pt x>0, x=9 solutie unica
as simple as that!!