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Calculati masa de hidroxid de sodiu care reactioneaza cu 300 ml de hcl de cm=0.2 mol/L

Răspuns :

Edith14
NaOH + HCl = NaCl +H2O
M NaOH = 40g/mol
M HCl = 36,5g/mol
CM = n/v => n= CM•v= 0,2mol/L • 0,3L = 0,06moli HCl
n=m/M => m= n•M= 0,06moli • 36,5g/mol = 2,19g HCl
40g NaOH..................36,5g HCl
xg NaOH......................2,19g HCl
=> x=2,4g NaOH

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