cine ma ajuta si pe mine va rog urgent
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1.|x| = x pt. x > 0 si -x pt. x<0
Pt. x > 0 => 2x - x +3 = 0 > x = -3 nu este pozitiva
Pt. x < 0 => 2x-(-x) +3 = 0 > 3x = -3, x = -1 => A={-1}
2.f(x) >=0 daca are forma (x+a)^2 + b , cu b > 0
f = (x-(m-1))^2 -(m-1)^2 + m +5 => -(m-1)^2 + m +5 > 0
-m^2 +2m -1 +m+5 =-m^2+3m+4 >= 0, delta = 9+16=25 => m=-1 si m=4
-m^2+3m+4 >= 0 ptr. m intre radacini => -1 <= m <= 4
3. Comb.de 10 luate 2 = comb. 10 Luate 8 (compl.) => rez. = 0