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[tex] {x}^{2} - 5x+4 = 0[/tex]

Răspuns :

Abcdef231

x^2-5x+4=0

/\=b^2-4ac=>/\=25-16=>/\=9

X1=(5+3)/2=>X1=4

X2=(5-3)/2=>X2=1

Abc112
[tex] {x}^{2} - 5x + 4 = 0[/tex]

[tex] {x}^{2} - 4x - x + 4 = 0[/tex]

[tex]x(x - 4) - (x - 4) = 0[/tex]

[tex](x - 4)(x - 1) = 0[/tex]

[tex]x - 4 = 0 = > x = 4[/tex]

[tex]x - 1 = 0 = > x = 1[/tex]

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