2x + 5y - 10 = 0
2x = -5y+10
2x = 10 - 5y
x = (10-5y)/2
x = 10/2 - 5y/2
x = 5 - 5y/2
x ∈ N => 5 - 5y/2 ≥ 0 => 5 ≥ 5y/2 => 1 ≥ y/2 => y/2 ≤ 1 => y ≤ 2
x ∈ N => y/2 ∈ N => y = 2, y = 0.
y = 2 => x = 5 - 5·2/2 => x = 5-5 => x = 0 => (x=0, y=2)
y = 0 => x = 5 - 5·0/2 => x = 5 - 0 => x = 5 => (x=5, y=0)
Cele doua perechi sunt:
(x=0, y=2); (x=5, y=0)
