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a fost răspuns

Calculați (ab) la puterea 2
a) a=-3; b=-1;
b) a=-4; b=+2;
c) a=+9; b=-1;
d) a=-3; b=-2

Răspuns :

Abc112
[tex]a)a = - 3[/tex]

[tex]b = - 1[/tex]

[tex] {(ab)}^{2} = { [ - 3 \times ( - 1)]} ^{2} = {3}^{2} = 9[/tex]

[tex]b)a = - 4[/tex]

[tex]b = + 2[/tex]

[tex] {(ab)}^{2} = {[ - 4 \times ( + 2)]} ^{2} = {( - 8)}^{2} = 64[/tex]

[tex]c)a = + 9[/tex]

[tex]b = - 1[/tex]

[tex] {(ab)}^{2} ={ [9 \times ( - 1)]} ^{2} = {( - 9)}^{2} = 81[/tex]

[tex]d)a = - 3[/tex]

[tex]b = - 2[/tex]

[tex] {(ab)}^{2} = {[ - 3 \times ( - 2)]} ^{2} = {6}^{2} = 36[/tex]
Icecon2005

Calculați (ab) la puterea 2

a) a=-3; b=-1; (a×b)²= [( - 3)×( - 1)]² = 3² = 9


b) a=-4; b=+2; (a×b)²= [( - 4)×(2)]² = (- 8)² = 64


c) a=+9; b=-1; (a×b)²= [( 9)×(-1)]² = (- 9)² = 81


d) a=-3; b=-2 (a×b)²= [( -3)×(-2)]² = (+6)² = 36

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