[tex]log_ab = \frac{1}{log_ba}
atunci \frac{1}{log_8 5} = \frac{1}{\frac{1}{log_58}} = log_58[/tex]
[tex]=\ \textgreater \ a = (5^{2})^{log_58} =\ \textgreater \ a = 5^{2log_58} =\ \textgreater \ a = 5^{log_516} =\ \textgreater \ a = 16[/tex]
conform formulei [tex] a^{log_ax} = x [/tex] ∀ x > 0
