Aria laterala a piramidei = Pb x ap / 2
ap = h fetei
o fata => are laturile laterale de 13 si baza de 10 ( triunghi isoscel )
conform teoremei lui Pitagora
ap ² = l ² - ( b/2)² = 13² - 5² = 169 - 25 = 144
ap = √144 = 12
A lat = 4 x 10 x 12 / 2 = 480 / 2 = 240 u.m.²
Volumul piramidei = Ab x h / 3
Aria bazei piramidei patrulatere = l² = 10² = 100 u.m.²
V = 100 x 12 / 3 = 400 u.m.³