h = (c1 x c2)/ip
3√3 = 6 x c2 / ip
ip = 6c/3√3 = 6c√3/9 = 2c√3/3
conform Teoremei lui Pitagora => ip² = 6² + c²
ip = √(36 + c²)
2c√3/3 = √(36 + c²) ridicam ambele parti la patrat
4c²×3/9 = 36 + c²
12c² = 9(36 + c²)
12c² = 324 + 9c²
12c² - 9c² = 324
3c² = 324
c² = 324 : 3
c² = 108
c = √108 = 6√3
ip = √[(6√3)² + 6²] = √(108 + 36) = √144 = 12 cm
