Răspuns :
6
a) m(EF)+m(EDF)=360°
m(EF)+2m(EF)=360°
3m(EF)=360°
m(EF)=360°/3=120°
m(EDF)=2m(EF)=2×120°=240°
b) m(EF)+m(EDF)=360°
m(EF)+4m(EF)=360°
5m(EF)=360°
m(EF)=360°/5=72°
m(EDF)=4m(EF)=4×72°=288°
a) m(EF)+m(EDF)=360°
m(EF)+2m(EF)=360°
3m(EF)=360°
m(EF)=360°/3=120°
m(EDF)=2m(EF)=2×120°=240°
b) m(EF)+m(EDF)=360°
m(EF)+4m(EF)=360°
5m(EF)=360°
m(EF)=360°/5=72°
m(EDF)=4m(EF)=4×72°=288°
8.
a) m(BAC) =360° -m(BOC) =360°-80°=280°
b) m(BAC) =360°-m(BOC) =360°-92=268°
a) m(BAC) =360° -m(BOC) =360°-80°=280°
b) m(BAC) =360°-m(BOC) =360°-92=268°