Răspuns :
1.
A={x e Z | √35 < x <√101}
→ x ∈{√36,√49,√64,√81,√100}
A={6,7,8,9,10}
2.
h=l √ 3/2
h=6√3/2
h=3√3 cm
A=l²√3/4
A=36√3/4
A=9√3 cm²
A={x e Z | √35 < x <√101}
→ x ∈{√36,√49,√64,√81,√100}
A={6,7,8,9,10}
2.
h=l √ 3/2
h=6√3/2
h=3√3 cm
A=l²√3/4
A=36√3/4
A=9√3 cm²
[tex] \mathbf{2.} \: \: \: \: \: \: \: \: \: \: \: \: \it h_{triunghi ~echilateral} = \mathbf{\frac{l \sqrt{3} }{2}} = \frac{6 \sqrt{3} }{2} = 3 \sqrt{3} \: cm \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: A_{triunghi ~echilateral} = \it \mathbf{ \frac{l^{2} \sqrt{3} }{4} } = \frac{ {6}^{2} \sqrt{3} }{4} = \frac{36 \sqrt{3} }{4} = 9 \sqrt{3 } \: cm^{2} [/tex]