Răspuns :
La inceput: numar egal de alune ramase + cat au cheltuit
M /----------/ +31
P /----------/ +26
R /----------/ +33
adunam alunele ramase, adica 3 segmente, obtinem un numar de 4 ori mai mult decat cat au cheltuit impreuna:
3segmente=(31+26+33) x 4
3segmente=90x4=360
1segment=360:3=120alune
la inceput au avut:
M 120+31 = 151 alune
P 120+26= 146 alune
R 120+33 = 153 alune
31+36+26=93au cheltuit in total
93×4=372 aveau toți la inceput
372÷3=124 avea fiecare
93×4=372 aveau toți la inceput
372÷3=124 avea fiecare