Na2CO3
raport atomic=r.a.=2Na:1C :3 O=2:1:3
raport de masa =r.m.=2ANa: AC :3AO=2.23: 12: 3.16=46:12:48=23:6:24
Masa moleculara= M= 46+12+48=106
Compozitie procentuala prin masa moleculara
106 g-------46g Na-------12 g C----------48 g O
100g-----------X------------Y--------------------Z
X=100.46:106=
Y=100.12:106=
Z=100.48:106=
Calculeaza!
