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75:{30-[24x(20-12:ax3)]:12+7}+3=8 plz ajutati.ma

Răspuns :

75 : {30 - [ 24 x ( 20 - 12 : a x 3 )] : 12+ 7} + 3=8

75 : {30 - [ 24 x ( 20 - 12 : a x 3 )] : 12+ 7} = 8 - 3 = 5

30 - [ 24 x ( 20 - 12 : a x 3 )] : 12+ 7 = 75 : 5 = 15

30 - [ 24 x ( 20 - 12 : a x 3 )] : 12 = 15 - 7 = 8

[24 x ( 20 - 12 : a x 3 )] : 12 = = 30 - 8 = 22

24 x ( 20 - 12 : a x 3 ) = 22 × 12

24 x ( 20 - 12 : a x 3 ) = 264

20 - 12 : a x 3 = 264 : 24

20 - 12 : a x 3 = 11

12 : a x 3 = 20 - 11

12 : a x 3 = 9

12 : a = 9 : 3

12 : a = 3

a = 12 : 3

a = 4 → numarul aflat prin metoda mersului invers