Răspuns :
i^3 =i*i^2=i*(-1)=-i
1/i = (1*i)/(i^2) = i/(-1) = -i
z= -i -3i - 3 = -3 - 4i => conj = -3 + 4i
1/i=-i²/i=-i
3i³=-3i (pt ca i³=i²*i=(-1)*i=-i)
atunci z=-i-3i-3=-3-4i
si z conjugat =-3+4i
as complex as that!!!
i^3 =i*i^2=i*(-1)=-i
1/i = (1*i)/(i^2) = i/(-1) = -i
z= -i -3i - 3 = -3 - 4i => conj = -3 + 4i
1/i=-i²/i=-i
3i³=-3i (pt ca i³=i²*i=(-1)*i=-i)
atunci z=-i-3i-3=-3-4i
si z conjugat =-3+4i
as complex as that!!!