I /__100____/
II/__100____/_100______/ P=600m
III/___100___/__100_____/___100____/
Avem 6 seg egale deci:600:6=100l(I butoi)
Scriem pe fiecare seg 100
100l x 2=200l(al II-lea butoi
100lx3=300 l (alIII-lea butoi)
R:100l(I butoi)
200l (iii-lea butoi)
verif:100+200+300=600(in total) 300l(al III-lea butoi)