Răspuns :
x= lungimea drumului
prima zi x/3 km parcursi, x-x/3=2x/3 km ramasi
a doua zi (2x/3)*2/5=4x/15 km parcursi, deci
x=x/3+4x/15+2,4 numitor comun 15
15x=5x+4x+36
6x=36
x=36/6=6 km
x= lungimea drumului
prima zi x/3 km parcursi, x-x/3=2x/3 km ramasi
a doua zi (2x/3)*2/5=4x/15 km parcursi, deci
x=x/3+4x/15+2,4 numitor comun 15
15x=5x+4x+36
6x=36
x=36/6=6 km