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AFLATI NUMARUL A DIN EGALITATEA 12+{2*[32*(A-24)*5]:4}*3=75

Răspuns :

Elakissup3bs9j
2x[32x(a-24)x5]:4=(75:3)-12
2x[32x(a-24)x5]:4=25-12
32x(a-24)x5=(13x4):2
32x(a-24)x5=52:2
A-24=(26:5):32
A-24=26/5x1/32
A-24=26/160(:2)
A-24=13/80
A=13/80+24
A=(13+80x24)/80
A=(13+1920)/80
A=1933/80
A=1941/80

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