Ad e |_ deci triunghiul ABD dr in D
BAD=30=>BD=AB/2
Aplicam teorema catetei in triunghiul ABC
AB^2=BDx48
Ab^2=AB/2x48
Simplifici 2 cu 48
AB^2=ABX24
==>AB=24 cm
Apoi Aplici pitagora in triunghiul ABC
AC^2=48^2-24^2
AC^2=2304-576
AC^2=1728
AC=24\/3
BD=24/2=12
Aplici pitagora in ABD
AD^2=576-144
AD^2=432
AD=12\/3