a)AB=rad[(1-3)^2+(4-3)^2]=rad(2^2+4^2)=rad(20)=2rad5
Analog rezulta:
AC=rad(4^2+2^2)=2rad5
BC=rad(2^2+2^2)=2rad2
Perim=2(2rad5+rad2)
b) Din teorie ec. dr. prin (x1,x2) si (y1,y1):
(x-x1)/(x2-x1)=(y-y1)/(y2-y1) de unde se scoate y functie de x
Aici :(x-1)/(3-1)=(y-3)/(8-3) -> y=(5x-2)/3
c) mijl.AC are coord. ((1+5)/2;(4+6)/2), adica (3;5)
