Răspuns :
a)
[tex]\frac{2}{9}x=\frac{4}{3}[/tex]
Produsul mezilor=produsul extremilor
6x=36
x=6
b)
[tex]-\frac{3}{5} y=0[/tex]
y=0
c)
2,5=4x
[tex]x=\frac{2,5}{4} =0,625[/tex]
d)
[tex]6x=\frac{5}{6} +4x\\\\2x=\frac{5}{6}\\\\x=\frac{\frac{5}{6}}{2}=\frac{5}{12}[/tex]
e)
[tex]1,2z-1=\frac{2}{5} \\\\1,2z=\frac{2}{5} +1\\\\1,2z=\frac{7}{5} \\\\z=\frac{7}{5} :\frac{12}{10} \\\\z=\frac{7}{5} \cdot \frac{10}{12} =\frac{7}{6}[/tex]
f)
[tex]1,(3)x+\frac{1}{4} =\frac{x}{3} -1\\\\\frac{12x}{9} +\frac{1}{4} =\frac{x}{3} -1\\\\\frac{4x}{3} +\frac{1}{4} =\frac{x}{3} -1[/tex]
Aducem la acelasi numitor comun 12 si eliminam numitorul:
16x+3=4x-12
12x=-15 |:3
4x=-5
[tex]x=-\frac{5}{4}[/tex]
g)
[tex]\frac{y-1}{2} +\frac{y+3}{3} =\frac{5}{12}[/tex]
Aducem la acelasi numitor comun 12 si eliminam numitorul:
6y-6+4y+12=5
10y+6=5
10y=-1
[tex]y=-\frac{1}{10}[/tex]
Un alt exercitiu gasesti aici: https://brainly.ro/tema/2730673
#SPJ5
Răspuns:
a. 2x/9=4/3
2x·3=4·9
6x=36=>x=36:6=>x=6
b. -3y/5=0
-3y=5·0=>y=0
c. 2,5=4x
x=2,5:4=>x=0,625
d. ⁶⁾6x=5/6+⁶⁾4x
36x=5+24x
36x-24x=5
12x=5=>x=5/12
e. 1,2z-1=0,4
1,2z=0,4+1
z=1,4:1,2
z=1,1(6)
f. (13-1)x/9+1/4=x/3-1
12x/9+1/4=x/3-1
⁴⁾4x/3+³⁾1/4=⁴⁾x/3-¹²⁾1
16x+3=4x-12
16x-4x=-12-3
12x=-15=>x=-15/12=>x=-1,25
g. ⁶⁾(y-1)/2+⁴⁾(y+3)/3=5/12
6y-6+4y+12=5
10y=5+6-12
y=-1/10=>y=-0,1