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a fost răspuns

X^2-x+3 supra x^2-x - x+2 supra x^2-x

Răspuns :

[tex]\dfrac{x^2-x+3}{x^2-x}-\dfrac{x+2}{x^2-x}=\dfrac{x^2-x+3-x-2}{x^2-x}=\dfrac{x^2-2x+1}{x(x-1)}=\\ \\ =\dfrac{(x-1)^2}{x(x-1)}=\boxed{\dfrac{x-1}{x},\forall x\in \mathbb{R}-\{0,1\}}[/tex]

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