Răspuns :
A) x=4/5-1/5
X=3/5
B)x-(2x5+1)/5=(4x3+1)/3-(1x2+1)/2
X-11/5=13/3-3/2
X=13/3-3/2+11/5
X=(10x13-15x3+6x11)/30
X=(130-45+66)/30
X=151/30
C)(3x5+1)/5-(x+1/2)=(1x5+1)/5
16/5-(x+1/2)=6/5
16/5-6/5=x+1/2
X=10/5-1/2
X=(2x10-5x1)/10
X=(20-5)/10
X=15/10 :5
X=3/2
X=3/5
B)x-(2x5+1)/5=(4x3+1)/3-(1x2+1)/2
X-11/5=13/3-3/2
X=13/3-3/2+11/5
X=(10x13-15x3+6x11)/30
X=(130-45+66)/30
X=151/30
C)(3x5+1)/5-(x+1/2)=(1x5+1)/5
16/5-(x+1/2)=6/5
16/5-6/5=x+1/2
X=10/5-1/2
X=(2x10-5x1)/10
X=(20-5)/10
X=15/10 :5
X=3/2
x+1/5=4/5 (faci produsul mezilor cu produsul extremilor)=> 5(x+1)=20=>5x+5=20=>5x=20-15=>5x=5=>x=5/5=>x=1