[tex] 2.a)\frac{1}{8}+ \frac{1}{8} \cdot 4= \frac{1}{8}+\frac{4}{8}= \frac{5}{8} [/tex]
[tex]b)\frac{1}{6}+ \frac{1}{6}: \frac{1}{3} = \frac{1}{6}+\frac{1}{6}\cdot3= \frac{1}{6}+ \frac{3}{6}= \frac{4}{6}= \frac{2}{3} [/tex]
[tex]c)\frac{4}{9}+ \frac{3}{10}: \frac{6}{10} = \frac{4}{9}+\frac{3}{10}\cdot \frac{10}{6} = \frac{4}{9}+ \frac{1}{2}= \frac{8+9}{18}= \frac{17}{18}[/tex]
[tex]d)1 \frac{1}{3}\cdot2 \frac{1}{2}+6= \frac{3+1}{3}+ \frac{4+1}{2}+6= \frac{8+10+36}{6}= \frac{54}{6}=9 [/tex]
[tex]e)2 \frac{1}{7}\cdot1 \frac{1}{5}- \frac{1}{21}: \frac{1}{3} = \frac{15}{7}\cdot \frac{6}{5}- \frac{1}{21}\cdpt \frac{3}{1}= \frac{18}{35}-\frac{1}{7}= \frac{18}{35}- \frac{5}{35}= \frac{7}{35}= \frac{1}{5} [/tex]
[tex]f) \frac{5}{6}:( \frac{1}{3}+ \frac{1}{2}: \frac{1}{3}= \frac{5}{6}:( \frac{1}{3}+ \frac{1}{2}\cdot \frac{3}{1}= \frac{5}{6}:( \frac{1}{3} + \frac{3}{2}= \frac{5}{6}: \frac{11}{6}= \frac{5}{6}\cdot \frac{6}{11}= \frac{5}{11} [/tex]
