Răspuns :
b+c=23
bc=120
c=120/b
b+120/b=23
b^2-23b+120=0
b1,2=23+/-rad(529-480) / 2 = 23+/-rad49 /2 = 23+/-7 / 2 =>
b1=8
b2=15
Acestea sunt lungimile catetelor.
bc=120
c=120/b
b+120/b=23
b^2-23b+120=0
b1,2=23+/-rad(529-480) / 2 = 23+/-rad49 /2 = 23+/-7 / 2 =>
b1=8
b2=15
Acestea sunt lungimile catetelor.
S=c1+c2
S=23
P=c1•c2
P=120
X^2-SX+P=0
X^2-23X+120=0
∆= 23^2-480
∆=529-480
∆=49
X1=23-7/2
X1=8
X2=23+7/2
X2=15
c1=8cm
c2=15cm
S=23
P=c1•c2
P=120
X^2-SX+P=0
X^2-23X+120=0
∆= 23^2-480
∆=529-480
∆=49
X1=23-7/2
X1=8
X2=23+7/2
X2=15
c1=8cm
c2=15cm