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a fost răspuns

Se dau numerele:
a=214 , b=2, c=325
Sa se afle :
a) AxB+C-Bx[(A+BxC)-(A+C)]:5=
b)C+BxA+Bx[(C-A)xB-A]=

Răspuns :

Emap347
a) 214×2+325-2×[(214+2×325)-(214+325)]÷5=428+325-2[(214+650)-539]÷5=428+325-2(864-539)÷5=428+325-2×325÷5=428+325-130=623
b)325+2×214+2[(325-214)×2-214]=325+428+2(11×2-214)=325+428+2(222-214)=325+428+2×8=325+428+16=769

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