.
[tex] \frac{ ( \sqrt{3}-1 )^{2}+ \sqrt{12} }{( \sqrt{5}-1 )( \sqrt{5+1} )} + (\frac{1}{3})^{-2} [/tex]
[tex] \frac{3-2 \sqrt{3}+1+ \sqrt{4*3}}{ \sqrt{5} ^{2}- 1^{2} }+ \frac{ 3^{2} }{ 1^{2} } [/tex]
[tex] \frac{3-2 \sqrt{3}+1+2 \sqrt{3} }{5-1}+ \frac{9}{1} [/tex]
[tex] \frac{4}{4} +9=[/tex]
1+9=10∈N
