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Se amestecă 400g solutie 10% NaOH cu 400g solutie 50% NaOH si cu 200g apă. Sa se afle concentrația procentuală a soluției obținute

Răspuns :

Pokju8888
Sunt  in problema doua solutii .

c1=10                                  c1=md1.100:ms1
ms1=400 g                          md1=c1.ms1:100
c2=50                                   md1=10.400:100=40 g NaOH
ms2=400 g
mapa=200 g                       c2=md2.100:ms2
cf=?                                     md2=c2.ms2:100
                                            md2=50.400:100=200 g NaOH
cf=conc.finala               mdfinal=md1+md2=40+200=240 g NaOH

                                    msfinal=ms1+ms2=mapa
                                    msf=400+400+200=1000 g sol.

                                 cf=mdf.100:msf
                               cf=240.100:1000=24 la suta

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