Răspuns :
a)2x^2 + 6x - x - 3 - 2x^2 - 2x - 2 = 3x - 5
b)(x - 3)(2x - 3x + 3) + x^2 + 5x =
(x - 3)(-x + 3) + x^2 + 5x =
-x^2 + 3x + 3x - 9 + x^2 + 5x =
11x - 9
b)(x - 3)(2x - 3x + 3) + x^2 + 5x =
(x - 3)(-x + 3) + x^2 + 5x =
-x^2 + 3x + 3x - 9 + x^2 + 5x =
11x - 9
a) (2x-1)(x+3)-2(x²+x+1)= 2x²+6x-x+2 -2x²-2x-2= 3x-5
b) (x-3)(2x-3)(x-1)+x(x+5)=(2x²-3x-6+9)(x-1)+x²+5x=(2x²-9x+9)(x-1)+x²+5x=2x³-2x²-9x²+9x+9x-9+x²+5=2x³-10x²+23x-9
b) (x-3)(2x-3)(x-1)+x(x+5)=(2x²-3x-6+9)(x-1)+x²+5x=(2x²-9x+9)(x-1)+x²+5x=2x³-2x²-9x²+9x+9x-9+x²+5=2x³-10x²+23x-9