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Rezultatul calculului 2√18+3√18
Si 12
—
√8 +√12

Răspuns :

Abc112
[tex]2 \sqrt{18} + 3 \sqrt{18} = 2 \times 3 \sqrt{2} + 3 \times 3 \sqrt{2} = 3 \sqrt{2} (2 + 3) = 3 \sqrt{2} \times 5 = 15 \sqrt{2} [/tex]

[tex] \frac{12}{ \sqrt{8} } + \sqrt{12} = \frac{12 \sqrt{8} }{8} + 2 \sqrt{3} = \frac{3 \times 2 \sqrt{2} }{2} + 2 \sqrt{3} = 3 \sqrt{2} + 2 \sqrt{3} [/tex]
Nico234679ghd
2√18+3√18=5√18 =15√2
12/√8+√12=12/2√2+2√3 = 12/2(√2+√3) = 6/(√2+√3)= 6(√2-√3)/-1= -6(√2+√3)= -6√2+6√3

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