MC₆H₆ = 78g/mol
MC₇H₈ = 92g/mol
78x+92y = m
In conditiile date, doar toluenul se oxideaza la acid benzoic:
5C₆H₅-C⁻³H₃ + 6KMnO₄ + 9H₂SO₄ ⇒ 5C₆H₅-C⁺³OOH + 3K₂SO₄ + 6Mn⁺²SO₄ + 14H₂O
C⁻³ -6e⁻ ⇒ C⁺³ se oxideaza (agent reducator) ||5
Mn⁺⁷ +5e⁻ ⇒ Mn⁺² se reduce (ag.ox) ||6
MC₆H₅-COOH = 122g/mol , n = m/M = 36,3/122 = 0,29754 moli C₆H₅-COOH
n acid = n toluen = 0,29754 moli = y
n toluen = n benzen = 0,29754 moli (y=x)
m amestec = 78×0,29754+92×0,29754 = 50,58g ≈ 51g
