REZOLVARE:
a) AM = AB - MB = 12,5 - 10 = 2,5 cm
b) Aplicam Thales
[tex] \frac{AM}{AB}= \frac{AN}{AC} \\ \\ \frac{2,5}{12,5}= \frac{3}{AC} \\ \\ AC = \frac{3*12,5}{2,5}=3*5=15 \;cm [/tex]
c) Aplicam Thales
[tex]\frac{AN}{AC}= \frac{MN}{BC} \\ \\ \frac{3}{15}= \frac{MN}{10} \\ \\ MN= \frac{3*10}{15} =\frac{30}{15}=2\;cm[/tex]
d) Raporul dintre aria ΔAMN si aria ΔABC este egal cu patratul raportului a doua laturi corespondente ale celor 2 triunghiuri.
[tex] \frac{A\Delta AMN}{A\Delta ABC} = ( \frac{MN}{BC} )^{2} = ( \frac{2}{10} )^{2}=( \frac{1}{5} )^{2}= \frac{1}{25} [/tex]