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AndreeaAna1111
a fost răspuns

Se dau jumerele: a=(5×9+8+7):[6×5÷(9+1)+3]; b=(2+3)×10÷5+9+8+7+6+5+4+3+2+1; dau coroana

Răspuns :

Doinita18
a=5*9=45
45+8=53
53+7=60
9+1=10
6*5=30
30/10=3
3+3=6
60/6=10
a=10
b=2+3=5
10/5=2
5*2=10
10+9+8+7+6+5+4+3+2+1=55
b=55
Beatrice106
a=(5×9+8+7):[6×5:(9+1)+3]
a=(45+8+7):(6×5:10+3)
a=(53+7):(30:10+3)
a=60:(3+3)
a=60:6
a=10

b=(2+3)×10:5+9+8+7+6+5+4+3+2+1
b=5×10:5+9+8+7+6+5+4+3+2+1
b=50:5+9+8+7+6+5+4+3+2+1
b=10+9+8+7+6+5+4+3+2+1
b=55

Alte intrebari