Răspuns :
1. a) P = 4l unde l = latura pătratului
P= 12a+24 => l = (12a+24)/4 = [4(3a+6)]/4=3a+6
A=l^2 (l la puterea a 2-a)
A=(3a+6)(3a+6)=9a^2+36a+36
b) suprafața = arie
A= L*l
A= 96*81=7776 dam^2
(3a+6)^2=7776
(3a+6)^2=(2^5)*(3^5)
3a+6=4*9*sqrt(2*3)
3a+6=36*sqrt(6)
a+2=12sqrt(6)
a=12sqrt(6)-2
sqrt=radical
2.
a)
A=AB*BC
A=(2a+1)(2a-1)=4a^2-1=4095
4a^2=4096
a^2=1024
a=32
b)
AB=65hm=650dam
BC=63hm=630dam
2m=0,2dam
Trebuie calculate doua 4 arii care sunt egale doua câte doua.
A1=650*0,2=1300dam^2
A2=630*0.2=1260dam^2
Suprafata totala sarma: 1300*2+1260*2=5120 dam^2
P= 12a+24 => l = (12a+24)/4 = [4(3a+6)]/4=3a+6
A=l^2 (l la puterea a 2-a)
A=(3a+6)(3a+6)=9a^2+36a+36
b) suprafața = arie
A= L*l
A= 96*81=7776 dam^2
(3a+6)^2=7776
(3a+6)^2=(2^5)*(3^5)
3a+6=4*9*sqrt(2*3)
3a+6=36*sqrt(6)
a+2=12sqrt(6)
a=12sqrt(6)-2
sqrt=radical
2.
a)
A=AB*BC
A=(2a+1)(2a-1)=4a^2-1=4095
4a^2=4096
a^2=1024
a=32
b)
AB=65hm=650dam
BC=63hm=630dam
2m=0,2dam
Trebuie calculate doua 4 arii care sunt egale doua câte doua.
A1=650*0,2=1300dam^2
A2=630*0.2=1260dam^2
Suprafata totala sarma: 1300*2+1260*2=5120 dam^2