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Andreiutu05
a fost răspuns

A+b+c =130 (a. b. c) i. p(2.3.4)

Răspuns :

Nico234679ghd
a+b+c=130
{a, b, c} ip {2, 3,4}
a×2=b×3=c×4 =k
a=k/2
b=k/3
c=k/4
k/2+k/3+k/4= 130
6k+4k+3k /12=130
13k/12=130
k=130:13/12
k=130×12/13
k=120
a=k/2=120/2= 60
b=k/3=120/3=40
c=k/4=120/4= 30
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