se cunosc relatiile
c,m= n,mol/V(l)
m= nxM, unde M,NaOH= 40g/mol
ro= m/V--> ms= roxVs
c%= mdx100/ms
Din definitia concentratiei molare, se deduce
1000ml sol...contin........14,36mol NaOH
SAU, daca transform moli in grame,
1000ml sol.................m=14,36molx40g/mol=574,4g NaOH
SAU,daca transform volumul in masa
1000x1,437g sol..............574,4gNaOH ( 1ml=1cmcub)
in 100g..................................X aceasta este concentratia procentuala a solutiei, deoarece indica masa de NaOH dizolvata in 100g solutie
