[tex]\displaystyle\\
BD = \frac{BC}{2}= \frac{30}{2}=15~cm\\\\
\text{Aplicam teorema catetei in }~\Delta ABD~\text{ pentru a afla ipotenuza AB.}\\\\
BD^2 = BM \times AB\\\\
AB= \frac{BD^2}{BM}=\frac{15^2}{9}=\frac{225}{9}=25~cm\\\\
AC = AB = 25~cm\\\\
P = AB+AC+BC=25+25+30 = \boxed{\bf 80~cm}\\\\
\text{Aplicam teorema lui Pitagora in }~\Delta ABD~\text{ pentru a afla inaltimea AD.}\\\\
AD = \sqrt{AB^2 -BD^2}=\sqrt{25^2 -15^2}=\sqrt{625 -225}=\sqrt{400}=\boxed{\bf 20~cm}
[/tex]
