[tex]( \frac{1}{x+1}+ \frac{1}{x-1} + \frac{2}{x^{2}-1 } ) * \frac{x+1}{2} = \frac{(x+1)+(x-1)+2}{(x-1)(x+1)}* \frac{x+1}{2} = \frac{2x+2}{2(x-1)}= \frac{x+1}{x-1} [/tex]
Am inmultit a doua fractie cu (-1), apoi am adus primele trei fractii la acelasi numitor si s-au simplicat toate dupa aceea
