👤
a fost răspuns

Aratati ca :
E(x)=(1supra x²-2x - 1supra x²+2x +2supra x²-4) : 2x+6 supra x³-4x=x+2supra x+3 ,
 x∈R/{-3,-2,0,2} Va rog urgent


Răspuns :

Bunicaluiandrei
E(x) = [ 1/x(x-2) - 1/x(x+2) +2/(x+2)(x-2)]:2(x+3)/x(x+2)(x-2) =
=[(x+2-x+2+2x)/x(x+2)(x-2)]·x(x+2)(x-2)/2(x+3) = 2(x+2)/2(x+3) = (x+2)/(x+3)

Alte intrebari