👤
a fost răspuns

[( 1 supra 3 + 2 supra 21 ) : ( 1 supra 18 + 1 supra 14 ) - 2 intregi si 1 supra 2 ] × 8

Răspuns :

Geanina281
[(1\3+2\21):1\18+1\14)-2intregi 1\2]•8=
(1+2\3):1+1\2)5\2•8=
3\3:2\2-5\2•8=
3\3:3\2•8=
3\3:24\2=
3\15
("\„=supra)
SPER CA TE-AM AJUTAT
Ocafeluta
[(1/3+2/21)÷(1/18+1/14)-2intregi 1/2]*8=[(7/21=2/21)/(7/126+9/126)-5/2]*8=(9/21/16/126-5/2)*8=(9/21*126/16-5/2)*8=(54/16-5/2)*8=(27/8-20/8)*8=7/8*8=7

Alte intrebari