Ionii prezenti : H(+), OH(-)
Anod(+) : OH(-) -1e- => OH•
2OH• => H2O + 1/2O2 (se degaja)
Catod(-) : H(+) +1e => H•
2H• => H2 (se degaja)
Reactia globala: 2H2O => 2H2 + O2
n = m/M = 720/18 = 40 moli apa
2 moli H2O.................3 moli gaze (2H2+O2)
40 moli H2O.............x moli gaze
x = 60 moli gaze
teoretic : 60 moli gaze
practic: 60×90/100 = 54 moli gaze
pV = nRT => V = nRT/p = 54×0,082×310/1 = 1372,68L gaze