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Determinati molaritatea urmatoarelor solutii a) 3, 65 grame HCl dizolvate in 4 L solutie b) HNO3 30% (densitatea=1, 184 g/ cm^3)?

Răspuns :

Puia68
a)M,HCl= 36,5g/mol
n= m/M= 3,65g/36,5g/molL= 0,1mol
c=n/V= 0,1/4mol/l=.......................calculeaza

b) M,HNO3= 63g/mol
100g sol....contin..30g acid
100/1,184 cmcub...........30gacid
1000cmcub.............. m=355,2 g---> n=m/M= 5,64 mol---> c= 5,64mol/l