ρH₂O = 1g/cm³
VH₂O = 100cm³
ρ = m/V ⇒ m = ρ×V = 1×100 = 100g H₂O
m = 6,2g Na₂O
MNa₂O = 62g/mol , n = m/M = 6,2/62 = 0,1 moli Na₂O
Na₂O + H₂O ⇒ 2NaOH
1 mol Na₂O.............18g H₂O................2×40g NaOH
0,1 moli Na₂O............xg.............................yg
x = 1,8g H₂O
y = 8g NaOH
md final = 8g
ms final = 100+8-1,8 = 106,2g
Cf = mdf/msf×100 = 8/106,2×100 = 7,53%
